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.2x^2+8x-19=0
a = .2; b = 8; c = -19;
Δ = b2-4ac
Δ = 82-4·.2·(-19)
Δ = 79.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{79.2}}{2*.2}=\frac{-8-\sqrt{79.2}}{0.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{79.2}}{2*.2}=\frac{-8+\sqrt{79.2}}{0.4} $
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